Optimal. Leaf size=234 \[ -\frac{22 a^3 (g \cos (e+f x))^{5/2}}{15 f g \sqrt{a \sin (e+f x)+a} \sqrt{c-c \sin (e+f x)}}-\frac{22 a^2 \sqrt{a \sin (e+f x)+a} (g \cos (e+f x))^{5/2}}{35 f g \sqrt{c-c \sin (e+f x)}}+\frac{22 a^3 g \sqrt{\cos (e+f x)} E\left (\left .\frac{1}{2} (e+f x)\right |2\right ) \sqrt{g \cos (e+f x)}}{5 f \sqrt{a \sin (e+f x)+a} \sqrt{c-c \sin (e+f x)}}-\frac{2 a (a \sin (e+f x)+a)^{3/2} (g \cos (e+f x))^{5/2}}{7 f g \sqrt{c-c \sin (e+f x)}} \]
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Rubi [A] time = 1.14248, antiderivative size = 234, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 42, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.095, Rules used = {2851, 2842, 2640, 2639} \[ -\frac{22 a^3 (g \cos (e+f x))^{5/2}}{15 f g \sqrt{a \sin (e+f x)+a} \sqrt{c-c \sin (e+f x)}}-\frac{22 a^2 \sqrt{a \sin (e+f x)+a} (g \cos (e+f x))^{5/2}}{35 f g \sqrt{c-c \sin (e+f x)}}+\frac{22 a^3 g \sqrt{\cos (e+f x)} E\left (\left .\frac{1}{2} (e+f x)\right |2\right ) \sqrt{g \cos (e+f x)}}{5 f \sqrt{a \sin (e+f x)+a} \sqrt{c-c \sin (e+f x)}}-\frac{2 a (a \sin (e+f x)+a)^{3/2} (g \cos (e+f x))^{5/2}}{7 f g \sqrt{c-c \sin (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 2851
Rule 2842
Rule 2640
Rule 2639
Rubi steps
\begin{align*} \int \frac{(g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^{5/2}}{\sqrt{c-c \sin (e+f x)}} \, dx &=-\frac{2 a (g \cos (e+f x))^{5/2} (a+a \sin (e+f x))^{3/2}}{7 f g \sqrt{c-c \sin (e+f x)}}+\frac{1}{7} (11 a) \int \frac{(g \cos (e+f x))^{3/2} (a+a \sin (e+f x))^{3/2}}{\sqrt{c-c \sin (e+f x)}} \, dx\\ &=-\frac{22 a^2 (g \cos (e+f x))^{5/2} \sqrt{a+a \sin (e+f x)}}{35 f g \sqrt{c-c \sin (e+f x)}}-\frac{2 a (g \cos (e+f x))^{5/2} (a+a \sin (e+f x))^{3/2}}{7 f g \sqrt{c-c \sin (e+f x)}}+\frac{1}{5} \left (11 a^2\right ) \int \frac{(g \cos (e+f x))^{3/2} \sqrt{a+a \sin (e+f x)}}{\sqrt{c-c \sin (e+f x)}} \, dx\\ &=-\frac{22 a^3 (g \cos (e+f x))^{5/2}}{15 f g \sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}}-\frac{22 a^2 (g \cos (e+f x))^{5/2} \sqrt{a+a \sin (e+f x)}}{35 f g \sqrt{c-c \sin (e+f x)}}-\frac{2 a (g \cos (e+f x))^{5/2} (a+a \sin (e+f x))^{3/2}}{7 f g \sqrt{c-c \sin (e+f x)}}+\frac{1}{5} \left (11 a^3\right ) \int \frac{(g \cos (e+f x))^{3/2}}{\sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}} \, dx\\ &=-\frac{22 a^3 (g \cos (e+f x))^{5/2}}{15 f g \sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}}-\frac{22 a^2 (g \cos (e+f x))^{5/2} \sqrt{a+a \sin (e+f x)}}{35 f g \sqrt{c-c \sin (e+f x)}}-\frac{2 a (g \cos (e+f x))^{5/2} (a+a \sin (e+f x))^{3/2}}{7 f g \sqrt{c-c \sin (e+f x)}}+\frac{\left (11 a^3 g \cos (e+f x)\right ) \int \sqrt{g \cos (e+f x)} \, dx}{5 \sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}}\\ &=-\frac{22 a^3 (g \cos (e+f x))^{5/2}}{15 f g \sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}}-\frac{22 a^2 (g \cos (e+f x))^{5/2} \sqrt{a+a \sin (e+f x)}}{35 f g \sqrt{c-c \sin (e+f x)}}-\frac{2 a (g \cos (e+f x))^{5/2} (a+a \sin (e+f x))^{3/2}}{7 f g \sqrt{c-c \sin (e+f x)}}+\frac{\left (11 a^3 g \sqrt{\cos (e+f x)} \sqrt{g \cos (e+f x)}\right ) \int \sqrt{\cos (e+f x)} \, dx}{5 \sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}}\\ &=-\frac{22 a^3 (g \cos (e+f x))^{5/2}}{15 f g \sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}}+\frac{22 a^3 g \sqrt{\cos (e+f x)} \sqrt{g \cos (e+f x)} E\left (\left .\frac{1}{2} (e+f x)\right |2\right )}{5 f \sqrt{a+a \sin (e+f x)} \sqrt{c-c \sin (e+f x)}}-\frac{22 a^2 (g \cos (e+f x))^{5/2} \sqrt{a+a \sin (e+f x)}}{35 f g \sqrt{c-c \sin (e+f x)}}-\frac{2 a (g \cos (e+f x))^{5/2} (a+a \sin (e+f x))^{3/2}}{7 f g \sqrt{c-c \sin (e+f x)}}\\ \end{align*}
Mathematica [A] time = 1.86945, size = 158, normalized size = 0.68 \[ -\frac{(a (\sin (e+f x)+1))^{5/2} (g \cos (e+f x))^{3/2} \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right ) \left (\sqrt{\cos (e+f x)} (126 \sin (2 (e+f x))+515 \cos (e+f x)-15 \cos (3 (e+f x)))-924 E\left (\left .\frac{1}{2} (e+f x)\right |2\right )\right )}{210 f \cos ^{\frac{3}{2}}(e+f x) \sqrt{c-c \sin (e+f x)} \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )^5} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.338, size = 415, normalized size = 1.8 \begin{align*} -{\frac{2}{105\,f \left ( \left ( \cos \left ( fx+e \right ) \right ) ^{2}\sin \left ( fx+e \right ) +3\, \left ( \cos \left ( fx+e \right ) \right ) ^{2}-4\,\sin \left ( fx+e \right ) -4 \right ) \sin \left ( fx+e \right ) \cos \left ( fx+e \right ) } \left ( g\cos \left ( fx+e \right ) \right ) ^{{\frac{3}{2}}} \left ( a \left ( 1+\sin \left ( fx+e \right ) \right ) \right ) ^{{\frac{5}{2}}} \left ( -231\,i\sin \left ( fx+e \right ) \cos \left ( fx+e \right ) \sqrt{ \left ( \cos \left ( fx+e \right ) +1 \right ) ^{-1}}\sqrt{{\frac{\cos \left ( fx+e \right ) }{\cos \left ( fx+e \right ) +1}}}{\it EllipticE} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},i \right ) +231\,i\sin \left ( fx+e \right ) \cos \left ( fx+e \right ) \sqrt{ \left ( \cos \left ( fx+e \right ) +1 \right ) ^{-1}}\sqrt{{\frac{\cos \left ( fx+e \right ) }{\cos \left ( fx+e \right ) +1}}}{\it EllipticF} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},i \right ) +15\,\sin \left ( fx+e \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{4}-231\,i{\it EllipticE} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},i \right ) \sin \left ( fx+e \right ) \sqrt{ \left ( \cos \left ( fx+e \right ) +1 \right ) ^{-1}}\sqrt{{\frac{\cos \left ( fx+e \right ) }{\cos \left ( fx+e \right ) +1}}}+231\,i\sin \left ( fx+e \right ) \sqrt{ \left ( \cos \left ( fx+e \right ) +1 \right ) ^{-1}}\sqrt{{\frac{\cos \left ( fx+e \right ) }{\cos \left ( fx+e \right ) +1}}}{\it EllipticF} \left ({\frac{i \left ( -1+\cos \left ( fx+e \right ) \right ) }{\sin \left ( fx+e \right ) }},i \right ) +63\, \left ( \cos \left ( fx+e \right ) \right ) ^{4}-140\, \left ( \cos \left ( fx+e \right ) \right ) ^{2}\sin \left ( fx+e \right ) -294\, \left ( \cos \left ( fx+e \right ) \right ) ^{2}+231\,\cos \left ( fx+e \right ) \right ){\frac{1}{\sqrt{-c \left ( -1+\sin \left ( fx+e \right ) \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (g \cos \left (f x + e\right )\right )^{\frac{3}{2}}{\left (a \sin \left (f x + e\right ) + a\right )}^{\frac{5}{2}}}{\sqrt{-c \sin \left (f x + e\right ) + c}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (a^{2} g \cos \left (f x + e\right )^{3} - 2 \, a^{2} g \cos \left (f x + e\right ) \sin \left (f x + e\right ) - 2 \, a^{2} g \cos \left (f x + e\right )\right )} \sqrt{g \cos \left (f x + e\right )} \sqrt{a \sin \left (f x + e\right ) + a} \sqrt{-c \sin \left (f x + e\right ) + c}}{c \sin \left (f x + e\right ) - c}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (g \cos \left (f x + e\right )\right )^{\frac{3}{2}}{\left (a \sin \left (f x + e\right ) + a\right )}^{\frac{5}{2}}}{\sqrt{-c \sin \left (f x + e\right ) + c}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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